Difference between two numbers is 30. Twice the greater number is less than 7 times the smaller number by 5 . Find the numbers. Answer must be x=43 and y=13 (Do the question by steps)
Answers
Answered by
24
Answer:
Assume the two numbers as X and Y
x-y=30 ...........(1)
2x-7y=5 .........(2)
Multiplying (1)*2
2x-2y=60
2x-7y=5
____________
Subtract,5y=55
y=11
x=41
Answered by
15
Answer:
Greater no. is 43 and smaller no. 13 (As said by you.)
Step-by-step explanation:
Let the smaller no. be x(which is y) and the greater be x + 30
Now,
ATQ-
- 7x - 2(x +30) = 5
- 7x - (2x + 60) = 5
- 7x - 2x -60 = 5
- 5x - 60 = 5
- x = 65 ÷ 5
- x (which is y) = 13
- x + 30 (which is x)= 43
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