Difference between two numbers is 4 and its product is 96 find the numbers?
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Answer:
the two numbers can be (12, 8) and (-8, -12)
Step-by-step explanation:
Let the two numbers be x and y and x>y
Now it is given that the difference between two numbers is 4
And the product of the two numbers is 96
So, by condition,
x-y = 4
=> x = 4+y-------(1)
And x×y = 96
=> (4+y) ×y = 96
=> 4y+y^2 = 96
=> y^2 +4y -96 = 0
=> y^2 +12y-8y -96=0
=> (y+12) (y-8) = 0
=> y = -12, 8
If y = -12
Then x = 4+y = 4+(-12) = 4-12 = -8
And if y = 8
Then x= 4+y = 4+8 = 12
So, the two numbers can be (12, 8) and (-8, -12)
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