Question

Difference of 2 numbers is 96. If the numbers are in ratio of 7:3 find the numbers

Answer 1

Answer:

Let the two numbers be x and y ,

Now , according to the condition given in the question,

the two numbers are in the ratio of 3:5

=> x/y = 3/5

=> 5x = 3y _._. _._._._._.(1)

Now, again , as per the second condition given in the question,

the sum of the two numbers are 96

=> x + y = 96 _._._._._._._._.(2)

From equation (1) => x = 3y/5

Putting this value of x in equation (2),

=> 3y/5 + y = 96

=> 8y/5 = 96

=> y = 96×5/8

=> y = 60

Putting this either in equation (1) or (2), we will get

x = 36

Hence, we get the bigger number of the two as 60.

Hope your doubt must be cleared!

Have a nice day,

Thank you!

Answer 2

$\sf{\huge{\underline{\red{Given :-}}}}$

• Difference of two numbers is 96.

• The numbers are in ratio of 7:3 .

$\sf{\huge{\underline{\blue{To\:Find :-}}}}$

• The numbers involved .

$\sf{\huge{\underline{\pink{Solution :-}}}}$

Let the two numbers be 7x and 3x,

The Difference of two numbers is 96.

So, Difference between 7x and 3x is 96.

7x - 3x = 96 _______(1)

➝4x = 96

➝ x = $\cancel{\dfrac{96}{4}}$

➝ x = 24

• The first number is 7x = 7 × 24 = 168

• The second number is 3x = 3 × 24 = 72

The numbers involved are 168 & 72 .

_____________________________________

$\sf{\huge{\underline{\green{Verification :-}}}}$

7x - 3x = 96

We get,

• The first number is 7x = 7 × 24 = 168

• The second number is 3x = 3 × 24 = 72

➝ 168 - 72 = 96

➝ 96 = 96

_________________________________