Question

Difference of ages of father and son is 24 years two years back ago of father was twice the son's present age what is father's age now

Answer 1

Answer:

Step-by-step explanation:

Let us assume that age of son is x, and age of father is x + 24.

Two years ago ( x-2 and x+24-2 ) ,

Age of father = 2x ( Since it is given that age of father two years ago was two times son's present age )

x+24-2 = 2x

24-2 = 2x-x

22 = x

x = 22 ( This is the age of the son presently )

Age of father = x + 24 ( Since given in the question )

Age of father = 22+24

Age of father presently = 46 years.

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