difference of an AP whose first term is 4 the last time is 49 and sum of all it's term is 265
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Sl=49/2 [2*4+(49-1)d]=265
or, 49/2*8+48d=265
or, 196+48d=265
or, 48d=69
or, d=69/48
or, 49/2*8+48d=265
or, 196+48d=265
or, 48d=69
or, d=69/48
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