Math, asked by hamzamessagerou, 1 year ago

- Difference of the ages of two brothers is 2 and difference of squares of their ages is 16
the age of smaller one is

Answers

Answered by DeeptiMohanty
4
the age of smaller one is 2
Attachments:

hamzamessagerou: Wrong ans
DeeptiMohanty: ok
DeeptiMohanty: can i delete my answer
hamzamessagerou: sure
hamzamessagerou: There is ans '3' according to my ans key
hamzamessagerou: i explain this
hamzamessagerou: Let
age of 1st = x
2nd bro age = y
x-y=2 ......eq(1)
(x)^2 - (y)^2 = 16
(x-2) (x+2) = 16
where
(x-2) = 2
so
hamzamessagerou: 2(x+y) = 16
x+y = 8
x = 8-y
putting value of x in eq(1)
8 - y - y = 2
-2y = 2 - 8
-2y = -6
y = 3 Ans
Answered by Panzer786
2
Heya !!

Let the ages of two brothers be X years and Y years.

According to question,

X - Y = 2 -------equation (1)

And,

( X )² - ( Y )² = 16 ----------equation (2)

From equation (1) we get,

X - Y = 2

X = ( 2 + Y ) ----------equation (3)

Putting the value of X in equation (2)

( X )²- ( Y )² = 16

( 2 + Y )² - ( Y )² = 16

(Y)² + (2)² + 2 × 2 × Y - Y² = 16

y² - y² + 4 + 4Y = 16

4Y + 4= 16

4 ( Y + 1 ) = 12

Y + 1 = 3

y = 2
Putting the value of y in equation (3)

X = ( 2 + y ) = ( 2 + 2 ) = 4 years.

Hence,

Age of younger brother is 2 years.

★ HOPE IT WILL HELP YOU ★

hamzamessagerou: the ans of it is 3
hamzamessagerou: so it is wrong ans
Similar questions