Question

Difference of the compound interest received in 1st year and 2 nd year is 20% per annum at compound interest is 1200 then find the sum No spam and cheating

Answer 1

Answer:

hello account number 2

Answer 2

Compund interest for 1st year.

A= P$(1+\frac{20}{100} )$

$\huge\underlined{\sf{I = A-P}}$

$I_{1} = P(1+\frac{20}{100} )-P$

$Compound\: interest\: for\: 2nd\: year$

$I_{2} =P(1=\frac{20}{100})^2-P\\ \\difference =1200\\\\1200=P(1+\frac{20}{100} )^2-P-P(1+ \frac{20}{100} +P\\\\1200= P(1+\frac{20}{100} )^2-P(1+\frac{20}{100})\\ \\1200= P(1+\frac{20}{100} )^2((1+\frac{20}{100})-1)$

1200 = P×$\frac{120}{100}$×$\frac{20}{100}$

P = 5000