Question

Difference of the squares of two natural number is 37, then the sum of square of the number is

Answer 1

Answer: 685

Step-by-step explanation:

Let m be the biggest and n be the smallest of the two numbers whose difference of squares is 37

Then m² - n²=37

(m+n)(m-n)=37

As 37 is a prime number only factors of 37 are 37 and 1

So from this we can conclude that

m+n=37 and m-n=1

So m=19 and n=18

Sum of squares is m²+n²=19²+18²

=361+324

=685