Question

Differences delta h and delta e for the combustion of methane at 25 degree celsius is

Answer 1

Answer:

We already know that

ΔH=ΔEΔ$n_{g} RT$

ΔH-ΔE=Δ$n_{g}$RT

Delta H and Delta E is same for combustion of methane hence the difference is 0

$CH_{4}$+$2O_{2}$=$CO_{2} +2H_{2} O$

Δ$n_{g}$=18-17=1

ΔH-ΔE=1*8.31J/k/mol*300K

          =2493J/mol

Answer 2

Explanation:

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