Question

differenciate 100x⁹⁹​

Answer 1

Answer:

9900x⁹⁸ is the answer

Step-by-step explanation:

On differentiating,

(dx^n)/dx = nx^(n-1) = 99×100×x^(99-1) = 9900x⁹⁸

Answer 2

find★

• differenciate 100x⁹⁹

solution★

• we know that differenciation

• $\implies \: \: \frac{d}{dx} (x ){}^{n} = nx {}^{n - 1}$

• comparison 100(x)⁹⁹

• n=99

• $\implies \: \frac{d}{dx}(100 (x) {}^{99} )$

• $\implies99 \times 100x {}^{99 - 1}$

• $\implies9900x {}^{98}$

======================================

• differenciate 100x⁹⁹=$\star\pink{→9900x^98}$

=======================================

I hope it helps you