Differenciate cos(sin x)
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There are two functions here in the question.
1) cos function
and the
2) sin function.
Let f(y) = cos ( sin x )
Let u = sin x
Therefore,
f(y) = cos u
By applying the chain rule for differentiation,
dy/dx = dy/du + du/dx
dy/dx = d ( cos u ) / du + d sin x / d x
= - sin u + cos x
= - sin ( sin x) + cos x
since, u = sin x
= cos x - sin ( sin x )
Therefore,
d [ cos ( sin x )] / dx = cos x - sin ( sin x)
Hope this helps you !!
1) cos function
and the
2) sin function.
Let f(y) = cos ( sin x )
Let u = sin x
Therefore,
f(y) = cos u
By applying the chain rule for differentiation,
dy/dx = dy/du + du/dx
dy/dx = d ( cos u ) / du + d sin x / d x
= - sin u + cos x
= - sin ( sin x) + cos x
since, u = sin x
= cos x - sin ( sin x )
Therefore,
d [ cos ( sin x )] / dx = cos x - sin ( sin x)
Hope this helps you !!
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