Question

differenciate g(x) = 8-4x³+ 2x⁸
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Answer 1

Answer:

Given g(x) =

$8 - {4x}^{3} + {2x}^{8}$

by differentiationg g'(x)

$0 - {12x}^{2} + {16x}^{7}$

therefore g'(x) =

${16x}^{7} - {12x}^{2}$

Step-by-step explanation:

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Answer 2

find★

• differenciate g(x) = 8-4x³+ 2x⁸

★formula uses

$\star \pink{ \frac{d}{dx}(x {}^{n}) \implies nx {}^{n - 1} }$

• $\frac{d}{dx} (8 - 4x {}^{3} + 2x {}^{8} )$

• can we be written as differenciation rule different different differenciation

• $\implies \frac{d}{dx} (8) - \frac{d}{dx} (4x {}^{3} ) + \frac{d}{dx}(2x {}^{8} )$

• we know that constant term differenciation zero(0) so 8 differenciation zero and other term differenciation formula applied

• $\implies0 - 4 \times 3x {}^{3 - 1} + 2 \times 8x {}^{8 - 1}$

• $\implies - 12x {}^{2} + 16x {}^{7}$

answer★

• differenciate g(x) = 8-4x³+ 2x⁸→

$\star\pink{16x {}^{7} - 12x {}^{2} \: \: \: or \: \: 4x {}^{2}(4x {}^{5} - 3 ) }$

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