Math, asked by Anonymous, 9 months ago

Differenciate with respect to x and Check it is write or wrong f(x) = Sinx + Cosx + logx?​

Answers

Answered by Anonymous
2

Differentiating with respect to X we get

f'(x) = cosx - sinx + 1/x

we know that intigration is the reverse of differentiation so

 \int( \sin(x)  +  \cos(x)  +  log(x) )dx \\

on intigration we get

- cosx + sinx + 1/x + c

Which is equal to f(x)

Answered by roysupriyo10
1

f(x) =  \sin(x)  +  \cos(x)  +  ln(x)  \\ differentiating \: wrt \: x \\ f'(x) =  \cos(x) -  \sin(x)   +  \frac{1}{x} \\ integrating \: f'(x),\: we\: get\\</p><p>F(x)=\int f(x)\\</p><p>\intf(x)=-\cos(x)+\sin(x)+(xln(x)-x)

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