CBSE BOARD XII, asked by arpitmishracool4, 4 months ago

Differenciate y= sin^-1{2x/1+x^2}​

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Answers

Answered by kavithks
1

Answer:

Solution :

y=sin−1(2x1+x2)

⇒siny=2x1+x2

⇒cosy=1−sin2y−−−−−−−−√=1−(2x1+x2)2−−−−−−−−−−−−−√=1−x21+x2

Differentiating it w.r.t. x,

cosydydx=2(1+x2)−2x(2x)(1+x2)2

⇒cosydydx=2(1−x2)(1+x2)2

⇒dydx=1cosy(2(1−x2)(1+x2)2)

⇒dydx=1+x21−x2∗(2(1−x2)(1+x2)2)

⇒dydx=21+x2

Explanation:

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