Question

Differeniate y=e^
3 secx+4tanx
w.r.t.x​

Answer 1

Step-by-step explanation:

We have,

$y = e ^{3 \sec(x) + 4 \tan(x) }$

$\implies \frac{dy}{dx} = {e}^{3 \sec(x) + 4\tan(x) } .(3 \sec(x) \tan(x) + 4 \sec^{2} (x) )$

$\implies \frac{dy}{dx} = {e}^{3 \sec(x) + 4\tan(x) } . \sec(x) (3 \tan(x) + 4 \sec (x) )$