different energy transformations taking place during the free fall of body. Also practice
the expression for this condition.
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A body falling freely from a height experiences two forces. Its potential energy is changed into Kinetic energy.
Change in P.E = Change in K.E
m.g.h = 1/2 mv^2
Explanation:
As we know that
A body at a certain height "h" has potential energy stored in it. i.e.
Potential energy = m.g.h
Where
- m = mass of body
- h = height
- G = gravitational pull
Similarly, if a body falls freely from a certain height "h" then the potential energy stored in it is converted into Kinetic energy.
That is;
Change in P.E = Change in K.E
mgh = 1/2 mv^2
Also learn more
A man drops a 10 kg rock from the top of a 5 m ladder. What is its kinetic energy when it reaches the ground ?.what is its speed just before it hits the ground?
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