Question

different iate X+ cos x /tan x with respect to x?



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Answer 1

$\frac{d}{dx} \frac{x + cosx}{tanx} \\ \\ = \frac{tanx \frac{d}{dx} (x + cosx) - (x + cosx) \frac{d}{dx}tanx }{ {tan}^{2} x} \\ \\ = \frac{tanx(1 - sinx) - (x + cosx) {sec}^{2} x}{ {tan}^{2} x}$