Math, asked by aashi1610, 10 months ago

differentation of inverse trigonometry function tan-1(cotx)​

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Answered by Needthat
0

y =  { \tan}^{ - 1} ( \cot \: x) \\  \\y =  { \tan}^{ - 1} ( \tan \:( \frac{\pi}{2} -   x)) \\ y =  \frac{\pi}{2}  - x \\  \\ diff \\  \\  \frac{dy}{dx}  =  - 1 \\  \\

hope it helps

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