Question

Differential equation in clarauts equation y=sin(y-px)

Answer 1

Answer:

Step-by-step explanation:

The given Differential equation is

P = sin (y - x P)

As there is one Constant , so we have to differentiate it once with respect to x

y'= 0+ P

y'=P

Substituting the value of P in original equation

y = The given Differential equation is

P = sin (y - x P)

As there is one Constant , so we have to differentiate it once with respect to x

y'= 0+ P

y'=P

Substituting the value of P in original equation

y = sin-1y+xy