Math, asked by Mphnamte7740, 1 year ago

differential equation of general solution y=ae^(2x)+be^(3x)

Answers

Answered by shreyashdonal

1

∫dxy=∫dxae^(2x)+ ∫dxbe^(3x)

∫dxy=a∫dxe^(2x)+b∫dxe^(3x)

= ae^2x+be^3x Ans

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