Question

Differential equation tanxdy/dx + 2y=secx

Answer 1

Step-by-step explanation:

dy/dx +2y/tanx=secx/tanx=1/sinx

first order linear eqn

integrating factor =e^(2×lnsinx)=sinx × sinx

y× sinx × sinx = - cosx + C

y=C ×(cosecx)^2 - cotx × cosecx