Question

Differential of cos(ax²+b)w.r.t x is:

Answer 1

$y = cos(ax {}^{2} + b) \\ \frac{dy}{dx} = \frac{d(cos(ax {}^{2} + b)}{dx} \\ \frac{dy}{dx} = - sin(ax {}^{2} + b) \frac{d(ax {}^{2} + b) }{dx} \\ \frac{dy}{dx} = - sin(ax {}^{2} + b)a2x \\ \frac{dy}{dx} = - 2ax \: sin(ax {}^{2} + b)$

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