Question

Differential of Log X and Cos X ​

Answer 1

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Differential of Log X = 1/X

Differential of Cos X = (-sin X)

Integration of Cos X = Sin X + C

where C is constant.

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Answer 2

$Here is your answer$

♠️$log^x$

$if y=log^x$

d.w.r.t.x

dy/dx = 1/x

♦️cosx

d.w.r.t.x

=-sinx

Hence proved..

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