Question

Differential of x²taninversex

Answer 1

Step-by-step explanation:

We have,

$y = {x}^{2} \tan^{ - 1} (x)$

Differnentiating both sides,

$\frac{dy}{dx} = 2x\tan^{ - 1} (x) + {x}^{2} . \frac{1}{1 + {x}^{2} }$

$\implies \frac{dy}{dx} = 2x\tan^{ - 1} (x) + \frac{ {x}^{2} }{1 + {x}^{2} }$