Question

Differential of y=log(4/x).

Answer fast...please...
Correct one will be brainliest

Your answer should be:-
dy/dx=-1/x​

Answer 1

I'm assuming the base of logarithm is 'e' or else you won't get

dy/dx = -1/x

Solution:

y = ln(4/x)

y = ln(4) - ln(x)

dy/dx = 0 - 1/x

dy/dx = -1/x

Answer 2

Answer:

dy/dx= d(log(4/x))/dx

consider 4x= x

applying chain rule,

dy/dx=x/4 ×4 ×(-1)×x^-2

dy/dx=-x ×x^-2

dy/dx=-x^-1

so, dy/dx=-1/x

hope it helps u!!!