Question

differential with respect to x :
=tan-1 4x/1+5x²

Answer 1

Answers : (2)

y=tan-1{(a+x)/(1-ax)}

dy/dx=1/[1+{(a+x)/(1-ax)}2].[(1-ax).1-(a+x).(-a)]/(1-ax)2

=[1/{(1-ax)2+(a+x)2}].[1-ax+a2+ax]

=(1+a2)/(1+a2x2+a2+x2)

=(1+a2)/(1+a2)(1+x2)

=1/(1+x2)

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Rinkoo Gupta

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