Question

Differentiale the following:
1. 3t^2+4t​

Answer 1

Answer:

(2*3)t^2-1 + 4(1)t^1-1

= 6t + 4

hope it helps

Answer 2

Question :-

Differentiate the following with respect to time :

1. 3t² + 4t

Answer :-

let k = 3t² + 4t

On differentiating k w.r.t time :

dk/dt

= d ( 3t² + 4t ) / dt

= 2(3t¹) + 1(4t°)

= 2(3 × t) + 1(4 × 1)

= 6t + 4

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Formula Used -

[ dtⁿ/ dt = nt^(n-1) ]

Abbreviation Used -

w.r.t => with respect to

____________

Thank You !