Question

Differentiate 1/(ax^2+bx+c) with respect to x.​

Answer 1

Answer:

《ANSWER》

Let  f(x)ax2+bx+c1

Thus by quotient rule

f′(x)=(ax2+bx+c)2(ax2+bx+c)dxd(1)−dxd(ax2+bx+c)

=(ax2+bx+c)2(ax2+bx+c)(0)−(2ax+b)=(ax2+bx+c)2−(2ax+b)

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Step-by-step explanation:

BY - JANNAT

Answer 2

Answer:

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