differentiate (1+x)/e^x
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Answered by
1
Answer:
The answer is =xex(1+x)2
Explanation:
We need the differentiation of a quotient
(uv)'=u'v−uv'v2
Here, u=ex, ⇒, u'=ex
v=1+x, ⇒, v'=1
Therefore,
dydx=ex(x+1)−ex(1+x)2
=xex+ex−ex(1+x)2
=xex(1+x)2
MARK AS BRAINLIEST
The answer is =xex(1+x)2
Explanation:
We need the differentiation of a quotient
(uv)'=u'v−uv'v2
Here, u=ex, ⇒, u'=ex
v=1+x, ⇒, v'=1
Therefore,
dydx=ex(x+1)−ex(1+x)2
=xex+ex−ex(1+x)2
=xex(1+x)2
MARK AS BRAINLIEST
dev2079:
answer is -xe^-x
Answered by
3
Answer:
-x/e^x
Step-by-step explanation:
Attachments:
thank u so much
ok welcome
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