Differentiate 1/x³+3x²
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Answer:
[ + 3 ] = -3x⁻⁴ + 6x
Step-by-step explanation:
We need to differentiate + 3x²
This can also be written as x⁻³ + 3x²
We know that the differentiation of xⁿ = nxⁿ⁻¹
We also know that [f(x) + g(x)] = [f(x)] + [g(x)]
Therefore applying the same formula in the given question
[ x⁻³ + 3x² ] = -3x ⁻³⁻¹ + 3 * 2x²⁻¹
= -3x⁻⁴ + 6x
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