Physics, asked by gauravgoswami207, 1 year ago

Differentiate 10cos2x​

Answers

Answered by pal69
2

d(10cos2x)/dx=10×(-2sin2x)=-20sin2x

Answered by ssara
1

Answer:

-20*sin(2*x)

Explanation:

(10*cos(2*x))'

(10)'*cos(2*x)+10*(cos(2*x))'

0*cos(2*x)+10*(cos(2*x))'

0*cos(2*x)+10*-sin(2*x)*(2*x)'

0*cos(2*x)+10*-sin(2*x)*((2)'*x+2*(x)')

0*cos(2*x)+10*-sin(2*x)*(0*x+2*(x)')

0*cos(2*x)+10*-sin(2*x)*(0*x+2*1)

0*cos(2*x)+10*2*(-sin(2*x))

0*cos(2*x)+10*-2*sin(2*x)

-20*sin(2*x)


ssara: thanks for choosing it brainliest! :))
gauravgoswami207: thnks to you for helping me
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