Differentiate 10cos2x
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Answered by
2
d(10cos2x)/dx=10×(-2sin2x)=-20sin2x
Answered by
1
Answer:
-20*sin(2*x)
Explanation:
(10*cos(2*x))'
(10)'*cos(2*x)+10*(cos(2*x))'
0*cos(2*x)+10*(cos(2*x))'
0*cos(2*x)+10*-sin(2*x)*(2*x)'
0*cos(2*x)+10*-sin(2*x)*((2)'*x+2*(x)')
0*cos(2*x)+10*-sin(2*x)*(0*x+2*(x)')
0*cos(2*x)+10*-sin(2*x)*(0*x+2*1)
0*cos(2*x)+10*2*(-sin(2*x))
0*cos(2*x)+10*-2*sin(2*x)
-20*sin(2*x)
ssara:
thanks for choosing it brainliest! :))
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