Question

Differentiate :
2 tanx + Secx - 3 cotx .​

Answer 1

Answer:

Given,

f(x) = 2 sec x + 3 cot x – 4 tan x

we need to find f’(x), so differentiating both sides with respect to x –

∴

2 sec x + 3 cot x – 4 tan x)

Using algebra of derivatives –

⇒ f’(x) =

Use the formula:

∴ f’(x) = 2(sec x tan x) + 3( – cosec2 x) – 4(sec2 x)

⇒ f’(x) = 2sec x tan x – 3cosec2 x – 4sec2 x

∴ f’(x) = 2sec x tan x – 3cosec2 x – 4sec2 x