Question

differentiate 2x^0*cos3x^0

can anyone plz solve this???​

Answer 1

Step-by-step explanation:

d/dx ( 2x⁰ cos 3x )

=> d/dx ( 2 cos 3x )

=> 2 d/dx ( cos 3x )

=> 2 × - sin 3x × 3

=> - 6 sin 3x