Question

Differentiate 2x+3sin3x-2cos2x

Answer 1

Answer:

2 + 9 cos3x + 4 sin2x

Step-by-step explanation:

We'll differentiate each part separately

Differentiating 2x, we get 2

Differentiating 3sin3x, we get 3x(3 cos3x)= 9cos3x

Differentiating -2cos2x. we get -2 x ( (-) x 2 sin 2x) = 4 sin2x

Putting all 3 together, we get the final answer as 2 + 9 cos3x + 4 sin2x