Differentiate (2x +8 )3
with respect to x
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Answer:
Use chain rule
Step-by-step explanation:
u = (2x+8)^3
du/dx = 3(2x+8)^2
v= 2x + 8
dv/dx = 2
dy/dx = u * dv/dx + v *du/dx
= (2x+8)^3 * 2 + (2x+8) * 3(2x+8)^2
simplify and u will get the answer
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