Question

differentiate 3 tanx -4 log x -7x^2 with respect to x

Answer 1

Step-by-step explanation:

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Answer 2

3sec^2(x) - 4/x - 14x

Explanation:

d(u+v)/dx = du/dx + dv/dx

derivative of tan(x) = sec^2(x)

derivative of 3tan(x) = 3sec^2(x)

derivative of logx = 1/x

derivative of -4logx = -4/x

derivative of x^2 = 2x

derivative of -7x^2 = (-7)2x = -14x

therefore derivative of 3 tanx -4 log x -7x^2 is equal to 3 sec^2(x) - 4/x - 14

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