Question

differentiate 3^xlogx​

Answer 1

3^x log x

= 3^xlog3/x ...

Answer 2

Answer:

3^xlogx log3 (1+logx)

Step-by-step explanation:

given 3^xlogx

let it be equal to Y

Y= 3^xlogx

taking log on Both sides

log Y = x ( logx ) ( log 3 )

differentiationg w.r.t. x

1/Y dy = [ x (1/x) + logx ] log 3 dx

dY/dx = Y log3 (1+logx)

dy/dx = 3^xlogx log3 (1+logx)