Differentiate 3sinx + 4
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Let y = 3sin(x) + 4
Differentiate the equation with respect to 'x',
=> dy/dx = y' = {3sin(x) + 4}'
= {3sin(x)}' + {4}'
= 3{sin(x)}' + {4}'
= 3cos(x) + 0
= 3cos(x)
Hence, the differential of 3sin(x) + 4 is 3cos(x).
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Pre-defined results used in the solution:
- {sin(x)}' = cos(x)
- (constant)' = 0
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