Physics, asked by akshattrivedi394, 9 months ago

Differentiate 3sinx + 4

Answers

Answered by Anonymous
0

Let y = 3sin(x) + 4

Differentiate the equation with respect to 'x',

=> dy/dx = y' = {3sin(x) + 4}'

= {3sin(x)}' + {4}'

= 3{sin(x)}' + {4}'

= 3cos(x) + 0

= 3cos(x)

Hence, the differential of 3sin(x) + 4 is 3cos(x).

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Pre-defined results used in the solution:

  • {sin(x)}' = cos(x)
  • (constant)' = 0
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