Math, asked by GREATBEAST8237, 7 months ago

Differentiate 3t3+2t2+6t+8 at t=1

Answers

Answered by pv438878
0

Answer:

3t^3 + 2t^2 + 6t + 8 (t=1)

3(1)^3 + 2(1)^2 + 6(1) + 8

3 + 2 + 6 + 8

19

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