Math, asked by ranit7060, 3 months ago

differentiate (3x+2)1^3 (x+1)​

Answers

Answered by Anonymous
1

Answer:

Answer

Let f(x)=

x+1

2

3x−1

x

2

f

(x)=

dx

d

(

x+1

2

)−

dx

d

(

3x−1

x

2

)

By quotient rule

f

(x)=[

(x+1)

2

(x+1)

dx

d

(2)−2

dx

d

(x+1)

]−[

(3x−1)

2

(3x−1)

dx

d

(x

2

)

dx

d

(3x−1)

]

=[

(x+1)

2

(x+1)(0)−2(1)

]−[

(3x−1)

2

(3x−1)(2x)−(x

2

)(3)

]

=

(x+1)

2

−2

−[

(3x−1)

2

6x

2

−2x−3x

2

]

=

(x+1)

2

−2

−[

(3x−1)

2

3x

2

−2x

]

=

(x+1)

2

−2

(3x−1)

2

x(3x−2)

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