Question

Differentiate:
5cosecxtanx - 7secxcotx​

Answer 1

Differentiate (x2-5x+8)(x3+7x+9) in three ways mentioned .... 2(1-cosx)<x2, x≠0 or otherwise prove that sin(tanx)≥ x for x ...

Answer 2

hey mate here is ur ans

let y= 5cosecxtanx-7secxcotx

y= 5×1/sinx.sinx/cosx-7×1/cosx.cosx/sinx

y = 5secx-7cosecx

dy/dx = 5secxtanx-(-cot²x)

= 5secxtanx+cot²x

hope it help u