Question

Differentiate a^x .?​

Answer 1

Step-by-step explanation:

y=a^x

both side multiply log

logy=loga^x

1/y dy/dx=loga.1

dy/dx=y loga

=a^x loga

Answer 2

Answer:

$a^{x}$·ln(a)

Step-by-step explanation:

Let y = $a^{x}$

⇒ x = log y to the base a.

Differentiating both sides w.r.t x,

⇒ 1 = $\frac{1}{y \ ln(a)}$ · $\frac{dy}{dx}$

⇒ $\frac{dy}{dx}$ = y · ln(a)

As y = $a^{x}$, Substituting it in,

∴ $\frac{d}{dx} a^{x}$ = $a^{x}$·ln(a)

Hoping that I have not made any mistakes, You're welcome.

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GeniusH