Physics, asked by anshikasharma9893, 7 months ago

differentiate (ax^2+bx+c) (x-d)

Answers

Answered by munigalaraju
0

Answer:

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Answered by biligiri
0

Answer:

Differentiate (ax^2 + bx + c) (x - d)

on multiplication we get

ax^3 + bx^2 + cx - adx^2 - bdx - cd

d/dx ( ax^3 + bx^2 + cx - adx^2 - bdx - cd

d/dx(ax^3) + d/dx(bx^2) + d/dx(cx)

- d/dx(adx^2) - d/dx(bdx) - d/dx(cd)

=> 3ax^2 + 2bx + c - 2adx - bd - 0 [ derivative of cd = 0 as they are constants ]

=> 3ax^2 + 2bx - 2adx + c - bd

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