Question

DIFFERENTIATE BETWEEN MEAN MEDIAN AND MODE...
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Answer 1

The "mean" is the "average" you're used to, where you add up all the numbers and then divide by the number of numbers. The "median" is the "middle" value in the list of numbers. ... If no number in the list is repeated, then there is no mode for the list.

Answer 2

$\bold{Okay, \: here \: we \: go . . .}$


$\huge{\mathfrak{\red{\underline{\underline{Mean}}}}}$

To arrive at the mean of a set of numbers, you add the numbers up and then divide the sum by the number of numbers you were dealing with. (This is just like calculating what is called the “average.”) If your number set is 12, 8, 7, 15, and 7, for example, you would first add all those numbers together (equaling 49) and divide that sum by the number of numbers in your set (5). The result is 9.8. That’s your mean!

$\huge{\mathfrak{\red{\underline{\underline{Median}}}}}$

This is the “middle” number in the set of numbers that you are dealing with. Think of it this way. Half of the numbers in the set are bigger than the median; half of the numbers are smaller. So to arrive at the median, simply put all the numbers in ascending order, with the smallest first. The number that is smack dab in the middle is the median. Aha you say, what if you have an even number of numbers in your set, not an odd number, so two numbers are in the middle? Well, the solution to that problem is easy; if that is the case, the median is midway between the two numbers that are in the middle of the set. So if your two middle two numbers are 7 and 9, your median is 8 (halfway in between).

$\huge{\mathfrak{\red{\underline{\underline{Mode}}}}}$

Okay, this is pretty simple. The mode is the number in a set that appears most frequently. If you are dealing with those numbers we cited at the outset - 12, 8, 7, 15, and 7 – the mode is 7, because 7 appears twice, more than any other number. What if you have a set of numbers in which every number appears just once? Simple! You then have a set of numbers that doesn’t have a mode.

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