Differentiate between the following pairs: [4]
(i) Sodium chloride and sodium sulphide (Using conc sulphuric acid)
(ii) Zinc nitrate and Lead nitrate (Using ammonium hydroxide)
(iii) Iron (II)chloride and Iron (III) chloride (Using sodium hydroxide)
(iv) Magnesium sulphate and Magnesium carbonate (Using dilute sulphuric acid)
Answers
Answered by
1
Answer:
1.When sodium chloride is heated with concentrated sulphuric acid in a round bottomed flask it gives sodium bisulphate and HCl.
2.Zinc nitrate reacts with ammonium hydroxide solution to form white precipitate. This white precipitate dissolves in excess ammonium hydroxide. Lead nitrate reacts with ammonium hydroxide solution to form white precipitate. This white precipitate does not dissolve in excess ammonium hydroxide.
3.ron (II) chloride is dissolved in water and then sodium hydroxide is added. ... A reddish brown precipitate is obtained, which confirms the presence of iron (HI) chloride. FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl.
4.idk the last one so sorry
Similar questions