differentiate by chain rule :- cos [ 3x - x² ] ??
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Answer:
The formula of cos(3x) is 4 cos^3(x) -3 cos(x). Let us discuss how this formula is derived. => cos(3x) = (2cos^2(x)-1)cos(x)-sin(x)2sin(x)cos(x).
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Answer:
formula used :- y = sin u
here , 'I'm is the function of 'X' .
dy/dx = d/dx( sin u )
dy/dx = cos u ( du/dx )
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Question:- to differentiate , cos [ 3x - x² ]
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Answer :-
☆ y = cos [ 3x - x² ]
==> dy/dx = - sin ( 3x - x² ) d/dx ( 3x - x² )
==> - sin ( 3x - x² ) ( 3 - 2x )
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