Math, asked by shajisurendran821, 2 months ago

differentiate cos (x³+x²+x+5) w.r.t x​

Answers

Answered by kristijakhua
0

\frac{d}{dx}\left(\cos \left(x^3+x^2+x+5\right)\right)

=-\sin \left(x^3+x^2+x+5\right)\frac{d}{dx}\left(x^3+x^2+x+5\right)

=-\sin \left(x^3+x^2+x+5\right)\left(3x^2+2x+1\right)

Answered by santhipriya01
1

Answer:

(cos(x3+x2+x+5))</p><p>=-\sin \left(x^3+x^2+x+5\right)\frac{d}{dx}\left(x^3+x^2+x+5\right)=−sin(x3+x2+x+5)dxd(x3+x2+x+5)</p><p>=-\sin \left(x^3+x^2+x+5\right)\left(3x^2+2x+1\right)=−sin(x3+x2+x+5)(3x2+2x+1)</p><p>

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