Question

differentiate
cot (x^2
sin 2x).​

Answer 1

Answer:

mark as brainlest answer

Answer 2

cotx−2sin2x=1

cosx−4sin

2

xcosx=1

cosx−4(1−cos

2

)cosx=1

Let cosx=z.

z−4(z−z

3

)=1

4z

3

+3z+1=0

(x+1)(2x−1)

2

=0

So, cosx=−1 and cosx=

2

1

.

∴ x=(2n+1)π. x=2nπ±

3

π

.