Question

differentiate (cot x)

Answer 1

HEY MISS !!!

HERE'S THE ANSWER..

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♠️ d ( cot x ) / d x

=> ( cot x ) '

=> ( cos x / sin x ) '

⏺️ Using quotient rule , i.e

✔️ ( u / v ) ' = [ ( u )' × v - u × ( v )' ] / v^2

=> [ ( cos x )' × sin x - cos x × ( sin x )' ] / ( sin x )^2

=> ( - sin x . sin x - cos x . cos x ) / ( sin x )^2

=> ( - sin^2 x - cos^x ) / sin^2 x

=> - ( sin^2 + cos^2 ) / sin^2 x

=> - 1 / sin^2 x

=> [ - cosec^2 x ] ✔️✔️



HOPE HELPED..

JAI HIND..

:-)