Question

differentiate cothx ...........​

Answer 1

heya mate✌

The derivative of cotangent can be found in the same way. However, this can be also done using the chain rule for differentiating a composite function: (cotx)′=(1tanx)′=−1tan2x⋅(tanx)′=−1sin2xcos2x⋅1cos2x=−cos2x sin2x⋅cos2x =−1sin2x........hope it may hlp❣

Answer 2

Answer:

the derivative of cothx

it is a hyperbolic function

Explanation:

cothx= -1/sinh^2x

hope it help u